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>5=2G5.?.5 <1.5/
56?B5 D85 =E<D9P<5F5< C85<6 31> 25 D1;5> ?ED
D851CDB?>?B= 4B1G5BC =ECD 25 B5=?F54
'E<< D85 =E<D9P<5F5< C85<6 6?BG1B4C 1>4 B5=?F5
%.;?270 =;*B
A=.7-*+5. 05*<< <1.5/
56?B5 D85 5HD5>412<5 7<1CC C85<6 31> 25 B5=?F54
D85C5BF9>7 DB1I =ECD 25 B5=?F54
*? 45D138 D85 7<1CC C85<6 6B?= D85 8?<45B 69BCD <96D 1D
D856B?>D D85> 1D D85 213; 1>4 D1;5 ?ED
88; <=8;*0. ,869*;=6.7=
#96D D85 4??B CD?B175 3?=@1BD=5>D 1>4 D1;5 9D ?ED
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